Fakeologist's Ball Earth Skeptic
Where I place all my flat earth research
Simple questions. What’s the answer? K?
Ab asks: “Where’s the curve”?
Well, since no one has answered that question as yet, allow me to reply with a question and a comment.
First, my comment : this shot with the building-below-waterline is pretty funny because it would rather seem to confirm the earth curvature – instead of its clearly stated intent to prove a flat earth:
Secondly, my question: what exactly is this expected curvature of earth so frequently referred to (and ‘demanded’) by flat earth proponents? The thing is, 1° out of a 360° circumference of 40,075km equals about 111km (1°=111km). For instance, London and Paris (distant about 333km) would only be ‘offset’ by 3°. If, by magic powers, one could see London from Paris (and vice versa), well – people would probably think the world is – indeed – flat :
Here’s what Toronto > New York would look like:
The link below contains a tool for calculating corrections in the earth’s curvature for measuring high points in a particular geographical area, as well as a separate tool for correcting for the height of the observer. (Unfortunately, the native unit of measurement is in feet/miles)
550 km X .62 + 341miles
According to the calculator on that page 341 miles (550 km) yields a distance correction of 77,800 feet or 14.73 miles. Add in the correction for a 6 foot tall observer and subtract 3 miles for a total of 11.73 miles of curvature between New York and Toronto (topographical irregularities notwithstanding).
For 25 miles (or 22 to account for the 6 foot tall observer) the correction is 323 feet, all of which should be obscured by the horizon. If the building is indeed 10 floors, even if it were a very fancy building with incredibly generous 30 foot ceilings, the entire building should be obscured by the curve of the horizon according to conventional standards.